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Linear Algebra Examples
50=2w+150=2w+1
Step 1
Rewrite the equation as 2w+1=502w+1=50.
2w+1=502w+1=50
Step 2
Step 2.1
Subtract 11 from both sides of the equation.
2w=50-12w=50−1
Step 2.2
Subtract 11 from 5050.
2w=492w=49
2w=492w=49
Step 3
Step 3.1
Divide each term in 2w=492w=49 by 22.
2w2=4922w2=492
Step 3.2
Simplify the left side.
Step 3.2.1
Cancel the common factor of 22.
Step 3.2.1.1
Cancel the common factor.
2w2=492
Step 3.2.1.2
Divide w by 1.
w=492
w=492
w=492
w=492
Step 4
The domain is the set of all valid w values.
{w|w=492}
Step 5